Check Leap Year Using Ternary Operator in C

Check Leap Year Using Ternary Operator in C

In this tutorial, we will write a C program to check whether a given year is a leap year or not using the ternary (conditional) operator.

Leap Year Rule

A year is a leap year if:

• It is divisible by 4 AND not divisible by 100
• OR it is divisible by 400

Mathematical Condition:

(year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)

C Program

#include <stdio.h>

int main() {
    int year;

    printf("Enter a year: ");
    scanf("%d", &year);

    // Using ternary operator
    ( (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0) ) 
        ? printf("%d is a Leap Year.\n", year)
        : printf("%d is NOT a Leap Year.\n", year);

    return 0;
}

Explanation

Step 1: Input

The program takes a year as input from the user.

Step 2: Condition Check

(year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)

• year % 4 == 0 → Divisible by 4
• year % 100 != 0 → Not divisible by 100
• year % 400 == 0 → Divisible by 400

Step 3: Ternary Operator

If the condition is true, it prints that the year is a Leap Year. Otherwise, it prints that it is NOT a Leap Year.

Sample Input

Enter a year: 2024

Output

2024 is a Leap Year.

Time Complexity

The program performs a constant number of operations. Therefore, the time complexity is O(1).

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