Finding the equation of a Line Given Two End Points
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C program for finding the equation of a Line Given Two End Points (x1,y1) and (x2, y2)
The equation for a line is Y = MX + C
Where M = Slope of a Line and C = Intercept
To Find the slope of a line
slope = (y2 - y1) / (x2 - x1)
To Find the intercept of the line, intercept = y1 - (slope) * x1
which would be same as, intercept = y2 - (slope) * x2
Source Code
#include <stdio.h>
#include <math.h>
void main()
{
float slope, intercept;
float x1, y1, x2, y2;
float dx, dy;
printf("Program to find the equation of a line given two end points\n");
printf("Enter X1: ");
scanf("%f", &x1);
printf("Enter Y1: ");
scanf("%f", &y1);
printf("Enter X2: ");
scanf("%f", &x2);
printf("Enter Y2: ");
scanf("%f", &y2);
dx = x2 - x1;
dy = y2 - y1;
slope = dy / dx;
// y = mx + c
// intercept c = y - mx
intercept = y1 - slope * x1; // which is same as y2 - slope * x2
printf("Equation of the line with end points (%.2f, %.2f) and (%.2f, %.2f) : Y = %.2fX %c %.2f\n", x1, y1, x2, y2, slope, (intercept < 0) ? ' ' : '+', intercept);
}
Output
Program to find the equation of a line given two end points
Enter X1: 2
Enter Y1: 3
Enter X2: 5
Enter Y2: 7
Equation of the line with end points (2, 3 and (5, 7) : Y = 1.33333X +0.333333
Press any key to continue . . .
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