2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder.
What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?
What is the smallest positive number that is evenly divisible by all of the numbers from 1 to 20?
Output is 232792560
উত্তরমুছুন--------------------------------
#include
#include
int main()
{
int num=20,flag=0;
while(flag==0)
{
if ((num%2)== 0 && (num%3) == 0 && (num%4) == 0 && (num%5) == 0 && (num%6) == 0
&& (num%7) == 0 && (num%8) == 0 && (num%9) == 0 && (num%10) == 0 && (num%11) == 0 && (num%12) ==0
&& (num%13) == 0 && (num%14) == 0 && (num%15) == 0 && (num%16) == 0 && (num%17) == 0 && (num%18)==0
&& (num%19) == 0 && (num%20) == 0)
{
flag=1;
printf("%d",num);
}
num++;
}
return 0;
}
well done
উত্তরমুছুন#include
উত্তরমুছুনmain()
{
int num=20,pl=0;
while(pl==0)
{
if ((num%2)== 0 && (num%3) == 0 && (num%4) == 0 && (num%5) == 0 && (num%6) == 0
&& (num%7) == 0 && (num%8) == 0 && (num%9) == 0 && (num%10) == 0 && (num%11) == 0 && (num%12) ==0
&& (num%13) == 0 && (num%14) == 0 && (num%15) == 0 && (num%16) == 0 && (num%17) == 0 && (num%18)==0
&& (num%19) == 0 && (num%20) == 0)
{
pl=1;
printf("%d",num);
}
num++;
}
return 0;
}
#include
উত্তরমুছুন#include
int main(int argc, char *argv[])
{
double nl_dbl_min = std::numeric_limits< double >::min();
double nl_dbl_dmin = std::numeric_limits< double >::denorm_min();
int *p = new int[2];
*p = 0;
*(p + 1) = 1;
double *my_dbl_min = reinterpret_cast< double* >(p);
std::cout << nl_dbl_min << '\t' << nl_dbl_dmin << '\t' << *my_dbl_min << std::endl;
delete p;
return 0
}