Program for the sum of 0 - N using the formula n (n+1) / 2.
Source Code
#include <stdio.h>
void main()
{
int N, sum = 0;
printf("Program for sum of all numbers from 0 - N\n");
printf("Enter N: ");
scanf("%d", &N);
sum = N * (N+1) / 2;
printf("The sum of all numbers between 0 and %d is: %d", N, sum);
}
Output
Program for sum of all numbers from 0 - N
Enter N: 100
The sum of all numbers between 0 and 100 is: 5050
#include"stdio.h"
উত্তরমুছুনmain(){
int i,n,sum=0;
printf("Enter value for n : \n");
scanf("%d",&n);
for (i=1;i<=n;i++){
sum+=i;
}
printf("sum is %d",sum);
}
#include
উত্তরমুছুনmain()
{
int n,i,sum=0;
printf("enter the value of n");
scanf("%d",&n);
sum=n*(n+2)/2;
printf("sum is %d",sum);
}
for(i=0;i<2;i++){
উত্তরমুছুনfor(j=0;j<2;j++){
printf("%d ",a[i][j]+b[i][j]);
if(j==1){
printf("\n");
}
#include
উত্তরমুছুনint main()
{
int N, on = 0;
printf("Program for On of all numbers from \n");
printf("Enter N: ");
scanf("%d", &N);
on = N * (N+2) / 4;
printf("on %d", on);
}
#include"stdio.h"
উত্তরমুছুনmain(){
int i,n,sum=0;
printf("Enter value for n : \n");
scanf("%d",&n);
for (i=1;i<=n;i++){
sum+=i;
}
printf("sum is %d",sum);
}